Programmer Humor

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Infallible Code (lemmy.ml)

submitted 3 days ago by sirico@feddit.uk to c/programmerhumor@lemmy.ml

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[–] Aedis@lemmy.world 33 points 2 days ago (13 children)

I'm partial to a recursive solution. Lol

def is_even(number):
    if number < 0 or (number%1) > 0:
        raise ValueError("This impl requires positive integers only") 
    if number < 2:
        return number
    return is_even(number - 2)

[–] tetris11@lemmy.ml 18 points 2 days ago* (last edited 2 days ago) (12 children)

I prefer good ole regex test of a binary num

function isEven(number){
   binary=$(echo "obase=2; $number" | bc)
   if [ "${binary:-1}" = "1" ]; then
         return 255
   fi
   return 0
}

[–] shalien@mastodon.projetretro.io 10 points 2 days ago (2 children)

@tetris11 @Aedis

Never touch my codebase please

[–] tetris11@lemmy.ml 3 points 2 days ago

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