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submitted 1 year ago* (last edited 1 year ago) by jim_stark@programming.dev to c/dotnet@programming.dev

The documentation uses is in the example for "declaration patterns" but the book I am reading uses a switch statement. But when I try to run the code I run into errors.

using System;

public class Program
{
  public static void Main()
  {
    var o = 42;

    switch (o) {
      case string s:
        Console.WriteLine($"A piece of string is {s.Length} long");
        break;

      case int i:
        Console.WriteLine($"That's numberwang! {i}");
        break;
    }
  }
}

Error:

Compilation error (line 7, col 6): An expression of type 'int' cannot be handled by a pattern of type 'string'.

EDIT

Changing from

var o = 42;

to

object o = 42;

worked.

Full code: https://github.com/idg10/prog-cs-10-examples/blob/main/Ch02/BasicCoding/BasicCoding/Patterns.cs

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[-] ex0dus 3 points 1 year ago* (last edited 1 year ago)

Your code does not follow the pattern matching syntax; I don't see "is" anywhere. That's what is actually doing the casting

Edit: I think I'm completely wrong about "is" being required

[-] jim_stark@programming.dev 2 points 1 year ago

I see.

The book uses a very specific scenario where o is an object that would accept any type. So using the object data type worked. Check the OP for the edit.

[-] Lmaydev@programming.dev 3 points 1 year ago* (last edited 1 year ago)

An integer will never be a string. Originally you create an integer variable so it's telling you the string case is pointless.

[-] RubberDucky@programming.dev 2 points 1 year ago* (last edited 1 year ago)

So c# in runtime already knows the type of o(unless you do some silly magic ofcourse) If you wanna change o for debug purposes you can try .GetType() and typeOf

You can check the type with

bool isString = o.GetType() == typeof(string);

(Sorry for any errors I'm on phone so code fiddlers aren't that great)

[-] jim_stark@programming.dev 1 points 1 year ago

The book uses a very specific scenario where o is an object that would accept any type. So using the object data type worked. Check the OP for the edit.

this post was submitted on 04 Jul 2023
12 points (100.0% liked)

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