This would probably cause a compiler error....

But assuming it doesn't the context is p_ch = the bits above... the code declaring p_ch isn't shown but I'm guessing that the value here is actuality a pointer to a pointer so nothing illegal would be happening.

Lastly... C++ is really lacking in guarantees so you can assign a char to the first byte of an integer - C++ doesn't generally care what you do unless you go out of bounds.

The reason I'm casting to void* is just pure comedy.

What I meant was:

In the screenshot it said x = *(++p) and iirc that is not the same as saying x = *(p++) or x = *(p += 1)

As in my example using ++p will return the new value after increment and p++ or p+=1 will return the value before the increment happens, and then increment the variable.

Or at least that is how I remember it working based on other languages.

I'm not sure what the * does, but I'm assuming it might be a pointer reference? I've never really learned how to code in c or c++ specifically. Though in other languages ( like PHP which is based on C ) there is a distinct difference between ++p and (p++ or p+= 1)

The last two behave the same. Though it has been years since I did a lot of coding. Which is why I asked.

I'll install the latest PHP runtime tonight and give it a try xD

Yes.

p++ == p+= 1 == p = p + 1 are all the same if you use it in an assignment.

++p is different if you use it in an assignment. If it's in its own line it won't make much difference.

That's the point I was trying to make.