Does the engine stay running and the throttle open to whatever degree it was before it was dropped? Because if not, the answer is practically nowhere. The mass of the wheels and tires is trivial compared to the rest of the mass of the car, and if the only energy you have in the system is the tires rotating without the power of the engine behind them I'd doubt it would be enough to move it more than a couple of feet. For instance my car weighs 3098 pounds and the wheels including tires are only something like 29 pounds each, so 119 pounds or so in total. They're only 3.84% of the total weight of the car. (Yes, I'm deliberately conflating weight and mass here, because I can't be arsed. Bite me.) You'd better slap it into neutral first as well, because otherwise without the engine running the freewheeling tires would have to fight the engine through the transmission and that'd rob you of basically all of the energy to begin with.

Otherwise, if you knew the mass and diameter of the wheels and the mass of the rest of the car, you could calculate this in a blithe sort of spherical-inelastic-cows sort of way. I think you'll be disappointed by the results. A layman's approximation without doing any fancy math on the matter would predict that you'd punt the car forwards in the above example for a single instant at the equivalent of about 3 miles per hour, after which it'd just be rolling under its own inertia.

However, you'd be quickly stymied in reality by the fact that dropping practically any car onto its wheels from 20 feet in the air would, at minimum, bottom out the suspension and possibly cause the tires to contact the insides of the wheel arches, stopping them dead. This is before we get into any other damage caused by such a drop. So you'd need a special suspensionless Solid Body Physics Car to test this with. I'm picturing something like an enormous pine box derby car.