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submitted 11 months ago* (last edited 11 months ago) by Ategon@programming.dev to c/advent_of_code@programming.dev

Day 6: Wait for It


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[-] reboot6675@sopuli.xyz 2 points 11 months ago

Golang

Pretty straightforward. The only optimization I did is that the pairs are symmetric (3ms hold and 4ms travel is the same as 4ms hold and 3ms travel).

Part 1

file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)

scanner.Scan()
times := strings.Fields(strings.Split(scanner.Text(), ":")[1])
scanner.Scan()
distances := strings.Fields(strings.Split(scanner.Text(), ":")[1])
n := len(times)
countProduct := 1

for i := 0; i < n; i++ {
	t, _ := strconv.Atoi(times[i])
	d, _ := strconv.Atoi(distances[i])
	count := 0
	for j := 0; j <= t/2; j++ {
		if j*(t-j) > d {
			if t%2 == 0 && j == t/2 {
				count++
			} else {
				count += 2
			}
		}
	}

	countProduct *= count
}

fmt.Println(countProduct)

Part 2

file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)

scanner.Scan()
time := strings.ReplaceAll(strings.Split(scanner.Text(), ":")[1], " ", "")
scanner.Scan()
distance := strings.ReplaceAll(strings.Split(scanner.Text(), ":")[1], " ", "")

t, _ := strconv.Atoi(time)
d, _ := strconv.Atoi(distance)
count := 0

for j := 0; j <= t/2; j++ {
	if j*(t-j) > d {
		if t%2 == 0 && j == t/2 {
			count++
		} else {
			count += 2
		}
	}
}

fmt.Println(count)

[-] morrowind@lemmy.ml 2 points 11 months ago

ah damn, didn't think of the symmetric pairs

this post was submitted on 06 Dec 2023
23 points (96.0% liked)

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