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[-] Naich@lemmings.world 40 points 6 months ago

Want to print out all odd numbers from 1 to 100? Easy:

for(_=[];_<+!![]+""+[]*[]+[]*[];_++)(_%+(!![]+!![])?console.log(_):[]);

[-] Naich@lemmings.world 17 points 6 months ago

Actually, I prefer this one: for(_=[];_<+!![]+""+[]*[]+[]*[];_++%+(!![]+!![])?[]:console.log(_));

[-] Naich@lemmings.world 18 points 6 months ago

Or this one without the "undefined" when run in a browser console:

for(_=[];_<+!![]+""+[]*[]+[]*[]-!![]-!![];_++%+(!![]+!![])?[]:console.log(_));_+!![]

[-] boredsquirrel@slrpnk.net 2 points 6 months ago

Wtf people, can somebody explain?

[-] Naich@lemmings.world 2 points 6 months ago

_ is a variable name, [] becomes 0 when converted to an integer, !![] becomes 1. The + "" + means that the integers 1, 0, 0 get converted to a string - "100", which gets converted back to an integer because it's in the for loop. And there's various other horrible conversions going on to make it all work.

this post was submitted on 14 Apr 2024
328 points (94.1% liked)

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