this post was submitted on 17 Jul 2026
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A brief recap: a few weeks ago I’d taken the $155,000 Range Rover I was testing out to run some errands with my wife in Plymouth, Minnesota. I was backing out of a parking space in front of my local Kohl’s when four cop cars came screaming up and “initiated a box and pin on the vehicle,” as the police report says. Hands on their guns, the officers ordered us out of the vehicle, patted us down, and eventually told us the Range Rover’s license plate—New Jersey 34 10 DTM—was stolen, they suspected the vehicle itself was stolen too, and they’d used Flock cameras to track me down over the last two days.

The scenario involving my wife and I is just one of many like it. Thomas noted that the system is 99% accurate today, but it’s performing 20 billion reads a month. That 1% error rate, of which I was a part of in June, makes for two hundred million misreads a month.

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[–] anomnom@sh.itjust.works 7 points 5 hours ago* (last edited 5 hours ago) (2 children)

How many digits to we need for 297,500,000 plates (as of 2026).

Plus we should probably include Canada and Mexico, since they have the same sized plates and cross the borders regularly.

Canada also has custom plates and different designs in each province too.

Also unless I’m mistaken, when Britain was in the EU, it didn’t use standardized plates like the rest of the member states, right?

[–] JohnEdwa@sopuli.xyz 11 points 4 hours ago (1 children)

There are no standard plates in the EU. The only matching thing is the country code on the left side.

[–] anomnom@sh.itjust.works 4 points 3 hours ago

That’s a lot closer to standardized than the Canada or the US.

[–] MangoCats@feddit.it 5 points 5 hours ago* (last edited 4 hours ago) (1 children)

6 characters (A-Z 0-9) gives you 2,176,782,336 combinations.

Even if you take out some confusing combos like O0, 1I, 5S, 8B ... 6 characters of 31 different kinds gives you 887,503,681

[–] Bbbbbbbbbbb@lemmy.world 2 points 4 hours ago (1 children)
[–] MangoCats@feddit.it 5 points 3 hours ago

the formula is number of possible symbols (letters, numbers) S to the power of the number of characters on the plate N, or S^N, so if you add one more character out of 31 possible symbols, then you multiply by (another) 31 available combinations.