It wont surprise you to hear that they don't! And TikZ is one of the main packages not well supported by XML/HTML converters. You need the authors to add alt text; best method I've seen is to make the TikZ/PGF in a standalone file, import as a png/pdf with the graphicx package, and add alt text that way.
If it's any consolation, you are almost certainly within ~3 years of understanding the solution and a dozen variants. It's not a super deep area. Probably doesn't really require calculus (you need continuous as in 'the lion doesn't teleport; that's cheating', but I think not much more).
Not FOSS, but ad free and its been able to find the hidden RSS feeds for things OK. FeedDemon at: http://bradsoft.com/
Probably not what you are after, but maybe someone with a similar question.
I saw a website offering this, but it looked very sketch to me... Hence asking strangers on the internet, which everyone knows is much safer.
Will do after the holidays. Let's assume I'm unlucky and they are uncooperative, suggested things to try next?
Somebody dropped a fair bit of cash and got Balders Gate 3 running for everyone. It's been big enough to fill a lot of time, but probably wont solve the problem when we're not all on vacation.
Glad they are thoroughly prepared, it seems?
Also looks like this wont be toooo big an eruption regardless.
Perhaps: (lim_{n->\infty} \sum_{m=1}^n 1/2^m ) + dim(Im(matrix([1,3,4],[2,6,8],[3,9,12])))
Ya'll are amazing! Thank you!
yep! this too.
Indeed! 2, as always, is a distraction. As the only even prime, it's the oddest of them all.
The important thing is that -1 is a square modulo p. Once it is you can use the (relatively fun and easy to do) Hensel's Lemma to compute exactly what the sqrt of -1 is in that particular p-adic ring.
So for which primes is -1 a square? A classic result of number theory states that these are the primes p such that p = 1 modulo 4. The primes like 5, 13, and 29 will have square roots of -1 in their p-adic rings, while 7, 11, and 31 will not.
Lots of rewarding math to explore around this question.
Artisian
joined 1 year ago
Would you then be posting your conclusions? Like, if you're gonna do that work on some of these posts anyway... may as well share.