(Temporary moratorium on main rule to encourage more posting on main. We reserve the right to arbitrarily enforce it whenever we wish and the right to strike this line and enforce mainposting with zero notification to the users because its funny)
A hexbear.net commainity. Main sure to subscribe to other communities as well. Your feed will become the Lion's Main!
Good comrades mainly sort posts by hot and comments by new!
State-by-state guide on maintaining firearm ownership
Domain guide on mutual aid and foodbank resources
Tips for looking at financials of non-profits (How to donate amainly)
Community-sourced megapost on the main media sources to radicalize libs and chuds with
Main Source for Feminism for Babies
Maintaining OpSec / Data Spring Cleaning guide
Remain up to date on what time is it in Moscow
My answer: Fuck this just give me a rifle and point me towards the enemy lines!
(2a^2^ (b+c)^2n^ - 1/2) x 2/2 = (4a^2^ (b+c)^2n^ - 1) x 1/2
Let's keep the 1/2 aside for now.
We can write 4a^2^ (b+c)^2n^ as 2^2^ a^2^ ((b+c)^n^ )^2^ and 1 as 1^2^
So (4a^2^ (b+c)^2n^ - 1) = ( 2a(b+c)^n^ )^2^ - 1^2^
Comparing with x^2^ - y^2^ we have x = 2a(b+c)^n^ and y = 1
With with x^2^ - y^2^ =(x+y) (x-y), we get:
(2a(b+c)^n^)^2^ - 1^2^ = (2a(b+c)^n^ + 1) (2a(b+c)^n^ - 1)
We can then cancel the common (2a(b+c)^n^ - 1) term from the numerators on both sides...
with the assumption that 2a(b+c)^n^ - 1 ≠ 0. If it's zero, then we introduce the issue of 0 x something = 0 x something.
0 x 1 = 0 x 2 = 0
We can't cancel the common zero and say that 1 = 2. So 0/0 or 1/0 is an issue, but with the assumption that it isn't 0, we can cancel it out.
I multiplied and dividing by 2 because in effect it changes nothing to the result as 2/2 = 1. But it helps to rearrange and simplify stuff.
Ah gotcha. Now it's all clear.