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[-] logicbomb@lemmy.world 175 points 8 months ago

Also, any number whose digits sum to a multiple of 3 is divisible by 3. For 51, 5+1=6, and 6 is a multiple of 3, so 51 can be cleanly divided by 3.

[-] Vorticity@lemmy.world 44 points 8 months ago* (last edited 8 months ago)

I'd forgotten this trick. It works for large numbers too.

122,300,223รท3 = 40,766, 741

1+2+2+3+2+2+3 = 15

[-] chooglers@lemmy.ml 51 points 8 months ago

threw up and died while reading this

[-] TokenBoomer@lemmy.world 15 points 8 months ago

I wish I could read ๐Ÿ˜ž

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[-] FlexibleToast@lemmy.world 26 points 8 months ago

The neat part is that if you add the numbers together and they're still too large to tell, you can do it again. In your example, you get 15. If you do it again, you get 6, which isn't the best example because 15 is pretty obvious, but it works.

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[-] paddirn@lemmy.world 27 points 8 months ago
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[-] MechanicalJester@lemm.ee 21 points 8 months ago

Fuck you and take an upvote for coming here to state what I was going to when I immediately summed 5+1 to 6 and felt clever thinking "well I do know it's not prime and divisible by 3" Shakes fist

I'll get you NEXT time logicbomb!

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[-] beckerist@lemmy.world 17 points 8 months ago

Same with 9. There are rules for every number at least through 13 that I once knew...

[-] logicbomb@lemmy.world 23 points 8 months ago

I only know rules for 2 (even number), 3 (digits sum to 3), 4 (last two digits are divisible by 4), 5 (ends in 5 or 0), 6 (if it satisfies the rules for both 3 and 2), 9 (digits sum to 9), and 10 (ends in 0).

I don't know of one for 7, 8 or 13. 11 has a limited goofy one that involves seeing if the outer digits sum to the inner digits. 12 is divisible by both 3 and 4, so like 6, it has to satisfy both of those rules.

[-] beckerist@lemmy.world 16 points 8 months ago

7 is double the last number and subtract from the rest

749 (easily divisible by 7 but for example sake)

9*2=18

74-18=56

6*2=12

5-12= -7, or if you recognize 56 is 7*8...


I'll do another, random 6 digit number appear!

59271

1*2=2

5927-2=5925

5*2=10

592-10=582

2*2=4

58-4=54, or not divisible

I guess for this to work you should at least know the first 10 times tables...

[-] logicbomb@lemmy.world 18 points 8 months ago

Another way to tell if 59271 is divisible by 7 is to divide it by 7. It will take about the same amount of time as the trick you're presenting, and then you'll already have the result.

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[-] Iron_Lynx@lemmy.world 10 points 8 months ago* (last edited 8 months ago)

And since both 3 and 17 are prime numbers, that makes 51 a semiprime number

[-] KevonLooney@lemm.ee 10 points 8 months ago

Which is not really rare under 100.

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[-] eager_eagle@lemmy.world 101 points 8 months ago* (last edited 8 months ago)

51 = 3*17

3*17 = 17 + 17 + 17

17 + 17 + 17 = (10+7) + (10+7) + (10+7)

(10+7) + (10+7) + (10+7) = 30 + 21

30 + 21 = 51

yup, math checks out

[-] _dev_null@lemmy.zxcvn.xyz 54 points 8 months ago* (last edited 8 months ago)

I think you skipped a step:

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Edit: Ohhhh, math by tens, I totally missed it. In that case, my mind wants to break it down to (10 * 5) + 1, and I'd still totally miss 17 as a possible factor.

[-] driving_crooner@lemmy.eco.br 17 points 8 months ago

You miss a couple os steps too.

First, lets define the axioms, we're using Peano's for this exercise.

Axiom 1: 0 is a natural number.

Jump to axiom 6, define the succession function s(n) where s(n) = 0 is false, and for brevity s(0) = 1, s(s(0)) = 2 and so on...

[-] BackOnMyBS@lemmy.world 21 points 8 months ago

51 = 3*17

3*17 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3

3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1)

(2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) = 34 + 17

34 + 17 = 51

๐Ÿ‘Œ

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[-] theneverfox@pawb.social 55 points 8 months ago

This is why I love the number 7. It's the first real prime number. All the others are "first"...1?2?3?5? No, those aren't prime numbers, they're "first" in a long line of not-prime numbers.

Then you get to 7. Is 27943 divisible by 7? If you take away 3 is it? If you add 4 is?

I have no clue, give me 10 minutes or a calculator is the only answer

That's what a real prime number is.

[-] Karyoplasma@discuss.tchncs.de 31 points 8 months ago* (last edited 8 months ago)

Take the last digit of the number, double it and subtract it from the rest. If that new number is divisible by 7, the original one is as well. For your example:

2794 - 6 = 2788

I know 2800 is divisible by seven, so 2788 is not. Thus 27943 is not divisible by 7.

Quick maff shows that neither subtracting 3 or adding 4 will make the original number divisible by 7. Adding 1 or subtracting 6 will tho.

[-] Tangent5280@lemmy.world 35 points 8 months ago

Our plan to find the witch has worked, boys! Get her!

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[-] match@pawb.social 13 points 8 months ago

Quick check for divisibility: subtract 7 from it. If the new number is divisible by 7, then the original number is too

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[-] postmateDumbass@lemmy.world 13 points 8 months ago* (last edited 8 months ago)

First non fibonacci prime

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[-] Resol@lemmy.world 32 points 8 months ago

Nobody told her that 100,000,001 is also divisible by 17

[-] OpenHammer6677@lemmy.world 10 points 8 months ago

Holy crapballs

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[-] Dagwood222@lemm.ee 30 points 8 months ago

Any number where the individual digits add up to a number divisible by '3' is divisible by 3.

51 = 5+1 = 6, which is divisible by three.

Try it, you'll see it always works.

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[-] Ubettawerk@lemmy.blahaj.zone 25 points 8 months ago
[-] kicksystem@lemmy.world 18 points 8 months ago

wait till she finds out that 0.99999... 9's to infinity is the same as 1

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[-] FlyingSquid@lemmy.world 17 points 8 months ago

Math is hard, so I'm just going to assume that's true and move on with my day.

[-] forrgott@lemm.ee 17 points 8 months ago

I love how every reply has like the opposite energy to the meme. I also find math to be generally awesome.

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[-] julianh@lemm.ee 16 points 8 months ago
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[-] AgentGrimstone@lemmy.world 16 points 8 months ago

Why did she share this? Does she hate us? I don't even know her.

[-] KSPAtlas@sopuli.xyz 15 points 8 months ago

When you start playing modded minecraft you get really good at multiplying and dividing by 144

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[-] EmperorHenry@discuss.tchncs.de 15 points 8 months ago

I don't get it, why is this a big deal?

[-] stillwater@lemm.ee 15 points 8 months ago
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[-] ickplant@lemmy.world 10 points 8 months ago

Fuck if I know, but look at the discussion this generated!

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[-] BigBlackCockroach@lemmy.world 12 points 8 months ago
[-] KingThrillgore@lemmy.ml 11 points 8 months ago

I used to do this thing where I would figure out if a number was prime or not and it kept me sane. Realizing this isn't, may have just caused my whole world to fall apart.

[-] autokludge@programming.dev 12 points 8 months ago

If you skipped checking divisibility by 3 you already messed up.

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this post was submitted on 22 Oct 2023
1261 points (96.3% liked)

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