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Irresistible
(mander.xyz)
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this post was submitted on 03 Jul 2024
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A schwarschild radius of 0.5 meters corresponds to about 56 Earth masses. So Richard must have accreted a bunch of mass before he collapsed.
Since you know the math, how long before it evaporated? Also, at what distance would an object feel 1G of acceleration?
Not OP. What would evaporate?
I think we don't know anymore what's going on with Richard. I believe he would consume Earth almost instantly, including all satellites and maybe the moon.
Didn't do the math myself, but internet says 1 G would be at about 48 km radius.
For an object heavier than the Earth, 1g radius will be greater than the radius of Earth. For 56 Earth masses that's sqrt(56) times bigger = 48000km.
A 56 Earth mass black hole will take 5.5e55 years to evaporate according to this calculator. A 100kg black hole (more close to what Richard used to be) is much smaller than the nucleus of an atom and will evaporate in 0.05 nanoseconds.
Curiously there was a paper recently that calculated that even if there was a small black hole in the center of the Sun, it would take millions of years for it to grow, because the aperture is so small not much can fit through, and the infalling gas heats up so much as to repel the rest, creating an internal hot bubble.
I am fairly sure Earth's radius is somewhat 6 km, so something with an 48 km radius would be 42 km above Earth's surface, where we experience 1 G.
Can you explain please, where I made a mistake?
Your mistake is thinking Earth is 6km in radius! :D 6km is how far you walk in an hour. Either you think Earth 1000 times too small or kilometer 1000 times too big.
๐ whooopsie! Haha. Yeah, it's somewhat 6000 km I mean. Sorry for my stupidity here today... Thank you very much for explaining my dumb mistake instead of making fun! Time to sleep now, I guess. Thank you!