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Fuck geometry (lemm.ee)
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[-] deikoepfiges_dreirad@lemmy.zip 4 points 3 weeks ago* (last edited 3 weeks ago)

funny Interpretation: in the complex plane, the imaginary axis is orthogonal to the real axis. so instead of the edge marked with i (AC), imagine an edge of length 1 orthogonal to that edge. It would be identical to AB, so ~~AC~~ CB is 0.

[-] propter_hog@hexbear.net 1 points 3 weeks ago

But then CB couldn't also be 0; wouldn't it be cos(1 + i)? Or something like that.

[-] deikoepfiges_dreirad@lemmy.zip 3 points 3 weeks ago

oh I mixed up the points, I meant to say CB is 0 in the end

this post was submitted on 29 Nov 2024
326 points (96.0% liked)

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